The force is inversely proportional to the square of the distance between
the two objects (using just the diameter of the earth is close enough).
Therefore for constant mass, halving the diameter of the earth would
INcrease the surface gravity by a factor of four. A smaller earth would
necessarily have a larger surface gravity.
JimC
----- Original Message -----
From: "Thomas R. Holtz, Jr." <tholtz@umd.edu>
To: <Ken.Carpenter@dmns.org>; <d_ohmes@yahoo.com>
Cc: <dinosaur@usc.edu>
Sent: Thursday, January 10, 2008 12:19 PM
Subject: RE: Conspiracy Theory- Earth's Expansion
But surface gravity = Gm/(r^2) (Where G = the gravitational constant).
Since G is a constant, and m would be fixed for the planet, a smaller
Earth
would necessarily have a smaller surface gravity.